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1864 United States presidential election in Michigan

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1864 United States presidential election in Michigan

← 1860 November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 8 0
Popular vote 79,149 68,513
Percentage 53.60% 46.40%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

The 1864 United States presidential election in Michigan took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose eight[1] representatives, or electors, to the Electoral College, who voted for president and vice president.[2]

Michigan was won by National Union candidate, incumbent Republican president Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic challenger George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a margin of 7.2%.[2]

As of the 2020 presidential election, this is the last time Ottawa County voted for a Democratic presidential candidate.[3]

Results

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1864 United States presidential election in Michigan[2]
Party Candidate Votes %
National Union Abraham Lincoln (incumbent) 79,149 53.60%
Democratic George B. McClellan 68,513 46.40%
Total votes 147,662 100%

See also

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References

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  1. ^ "1864 Election for the Twentieth Term (1865-1869)". Retrieved November 28, 2018.
  2. ^ a b c "1864 Presidential General Election Results - Michigan".
  3. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN 0786422173